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-0.0625x^2+2x+50=60
We move all terms to the left:
-0.0625x^2+2x+50-(60)=0
We add all the numbers together, and all the variables
-0.0625x^2+2x-10=0
a = -0.0625; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·(-0.0625)·(-10)
Δ = 1.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{1.5}}{2*-0.0625}=\frac{-2-\sqrt{1.5}}{-0.125} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{1.5}}{2*-0.0625}=\frac{-2+\sqrt{1.5}}{-0.125} $
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